GMendoza247
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A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were increased by a factor of four, calculate the displacement.

Respuesta :

Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

[tex]d = v_i t + \frac{1}{2}at^2[/tex]

now we know

[tex]d = 0 + \frac{1}{2}at^2[/tex]

now if the same car will accelerate from rest for four times of the previous time interval

then we will have

[tex]d = 0 + \frac{1}{2}a(4t)^2[/tex]

[tex]d = 16(\frac{1}{2}at^2)[/tex]

so the distance will be 16 times more

[tex]d = 1600 m[/tex]

deangullberry2176

Answer:

1600 m

Explanation:

if the time factor is tripled, the displacement is nine times greater

3:9 or in this case 4:16 (because the ratio is a square)

The time is increased by a factor of 4 so,

4^2=16

16*100 = 1600

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