What is the probability that a card selected at random from a standard deck of 52 cards is an ace or a heart? (enter the value of probability in decimal format and round it to two decimal places.)?

Sample space={all 52 cards} = all possible outcome

P(Ace) =4/52 = 0.0769
P(Heart) = 13/52 = 0.25

Just one card is drawn, so :
P(Ace ∪ Heart) = P(Ace) + P(Heart) - P(Ace ∩ Heart).
But with ONE card drawn P(Ace ∩ Heart) = 0 (Mutually exclusive/disjoint)
:
Hence P(Ace ∪ Heart) = 0.0769+0.25 = 0.3269 ≈ 0.33

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abidemiokin abidemiokin · Answer 2 · 2022-04-14T12:43:38+02:00

Probability is the likelihood or chance that an event will occur. If a card is selected at random from a standard deck of 52 cards, the probability that it is an ace or a heart is 17/52

What is probability?

Probability is the likelihood or chance that an event will occur. The formula for calculating probability is expressed as:

Probability = expected/total outcome

For a deck of card, the total outcome is 52 cards

Pr(selecting an ace) = 4/52 (there are 4 aces in a deck of card)

Pr(selecting a heart) = 13/52 (there are 13 hearts in a deck of card)

Find the required probability

Pr(an ace or a heart) = 4/52 + 13/52
Pr(an ace or a heart) = 17/52

Hence a card is selected at random from a standard deck of 52 cards, the probability that it is an ace or a heart is 17/52
Learn more on probability here: https://brainly.com/question/24756209