Respuesta :
M H2O = 18 g/mol
In 18 g of water we have 6,02 × 10^23 molecules.
18 g ----- 6,02 × 10^23
36 g ----- x
x = 36 g × 6,02 × 10^23 / 18 g = 12,04 × 10^23 = 1,204 × 10^24
Answer is 1,204 × 10^24
:-) ;-)
In 18 g of water we have 6,02 × 10^23 molecules.
18 g ----- 6,02 × 10^23
36 g ----- x
x = 36 g × 6,02 × 10^23 / 18 g = 12,04 × 10^23 = 1,204 × 10^24
Answer is 1,204 × 10^24
:-) ;-)
Water molecules present in the 36 gm of water in the terms of Na are 1.204 × 10²⁴.
What is Avogadro's number?
Avogadro's number gives the relation of the constituent particles of the molecules with that of the whole sample.
We know,
Mass of water = 18 g/mol
If 18 g of water contains 6.02 × 10²³ molecules then 36 gm will have,
36 × 6.02 × 10²³ / 18 = 1.204 × 10²⁴
Therefore, 1.204 × 10²⁴ molecules are present in 36 gms of water.
Learn more about Avogadro's number here:
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