Respuesta :
Empirical formula of caffeine is C₈H₁₀N₄O₂.
In 1 mol of caffeine we have 10 mol of hydrogen.
In 2,8 mol of caffeine we have x mol of hydrogen.
x = 2,8 mol * 10 mol / 1 mol = 28 mol
ANSWER: There are 28 mol of hydrogen.
:-) ;-)
In 1 mol of caffeine we have 10 mol of hydrogen.
In 2,8 mol of caffeine we have x mol of hydrogen.
x = 2,8 mol * 10 mol / 1 mol = 28 mol
ANSWER: There are 28 mol of hydrogen.
:-) ;-)
Answer:
Empirical formula of caffeine is C₈H₁₀N₄O₂. In 1 mol of caffeine we have 10 mol of hydrogen. In 2,8 mol of caffeine we have x mol of hydrogen. ANSWER: There are 28 mol of hydrogen.