Respuesta :
First find the slope height
h^2 = 38^2 + 21^2
43.42 yds
lateral area = 4 * area of each triangle = 4 * 1/2 * 42 * 43.42 = 3647 yd^2
It's D
h^2 = 38^2 + 21^2
43.42 yds
lateral area = 4 * area of each triangle = 4 * 1/2 * 42 * 43.42 = 3647 yd^2
It's D
Hello Gary!
Let slant height be s
Height = 38yd. = h
Side = 42yd. = a
S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.
Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²
In Short, The Correct Answer would be: Option "D". 3647 yd^2
Because: Base edge = 42 and Height = 38
So then, AL=a√a^2+4h^2=42·√42^2+4·38^2≈3646.99328. (3647 rounded up)
AL≈3646.99
Hope this Helps! Have A Wonderful Day! :)
Let slant height be s
Height = 38yd. = h
Side = 42yd. = a
S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.
Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²
In Short, The Correct Answer would be: Option "D". 3647 yd^2
Because: Base edge = 42 and Height = 38
So then, AL=a√a^2+4h^2=42·√42^2+4·38^2≈3646.99328. (3647 rounded up)
AL≈3646.99
Hope this Helps! Have A Wonderful Day! :)