Respuesta :
P1 = 0.75atm. P2 = ?
V1 = 150ml V2 = 500ml
T1 = 10°C T2 = 522°C
= 10+273 = 522+273
= 283K = 795K
By Gas Equation,
P1V1/T1 = P2V2/T2
0.75×150/283 = P2×500/795
P2 = 0.75×150×795/(283×500)
P2 = 0.63atm.
V1 = 150ml V2 = 500ml
T1 = 10°C T2 = 522°C
= 10+273 = 522+273
= 283K = 795K
By Gas Equation,
P1V1/T1 = P2V2/T2
0.75×150/283 = P2×500/795
P2 = 0.75×150×795/(283×500)
P2 = 0.63atm.
0.63atm will be exerted by the gas if the temperature is increased to 522 degrees Celsius and the volume changes to 500mL.
What is gas law?
An equal volume of all gases under the same conditions of temperature and pressure contains an equal number of molecules.
Given data:
[tex]P_1[/tex] = 0.75atm.
[tex]P_2[/tex] =?
[tex]V_1[/tex] = 150ml
[tex]V_2[/tex] = 500ml
[tex]T_1[/tex]= 10°C =10+273 = 283K
[tex]T_2[/tex]= 522°C
522+273 = 795K
Solution:
By Gas Equation,
[tex]\frac{P_1V_1}{T_1}[/tex]= [tex]\frac{P_2V_2}{T_2}[/tex]
Putting all the values in the given equation:
[tex]\frac{0.75 X 150}{283} =\frac{ P2 X 500}{795}[/tex]
[tex]P_2[/tex] = 0.63atm.
Hence, 0.63atm will be exerted by the gas if the temperature is increased to 522 degrees Celsius and the volume changes to 500mL.
Learn more about gas law here:
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