to factor this in ax^2+bx+c form where a is greater than 1, b=z+y ac=xy solve
so a=2 b=9 c=4
9=y+z c times a=4 times 2=8 what 2 numbers add up to 9 and mulitply to get 8? factor 8 8= 1 times8 2 times 4 if we add them up we get 1+8=9 check 2+4=6
the numbers are 1 and 8 split up the middle term 2x^2+1x+8x+4 group (2x^2+1x)+(8x+4) factor out/reverse distribute (x)(2x+1)+(4)(2x+1) reverse distribute useing distributive proerty ab+ac=a(b+c) (x+4)(2x+1)
