probability of one person owning a dog = 0.66
probability of picking 2 people who own dogs = 0.66 x 0.66 = 0.4356
Round answer as needed.
The probability of dog-ownership for two persons chosen at random is 0.4356
"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."
P(A) = n(A)/n(S)
where, n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.
For given question,
66% of people own dogs.
This means, the probability of dog-ownership for one person chosen at random = 0.66
We need to find the probability that two people selected at random own a dog.
The required probability would be,
⇒ P = 0.66 × 0.66
⇒ P = 0.4356
Therefore, probability of dog-ownership for two persons chosen at random is 0.4356
Learn more about probability here:
brainly.com/question/11234923
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