Calculate the work energy, w, gained or lost by the system when a gas expands from 15 l to 35 l against a constant external pressure of 1.5 atm

Respuesta :

The work done by the gas is about 30 L.atm

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Further explanation

The Ideal Gas Law and Work formula that needs to be recalled is:

[tex]\boxed {PV = nRT}[/tex]

[tex]\boxed { W = P \Delta V }[/tex]

where:

W = Work ( J )

P = Pressure ( Pa )

V = Volume ( m³ )

n = number of moles ( moles )

R = Gas Constant ( 8.314 J/mol K )

T = Absolute Temperature ( K )

Let us now tackle the problem !

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Given:

initial volume = Vo = 15 L

final volume = V = 35 L

constant pressure = P = 1.5 atm

Asked:

word done by the gas = W = ?

Solution:

[tex]W = P \Delta V[/tex]

[tex]W = P \times ( V - Vo )[/tex]

[tex]W = 1.5 \times ( 35 - 15 )[/tex]

[tex]W = 1.5 \times 20[/tex]

[tex]W = 30 \texttt{ L.atm }[/tex]

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Conclusion:

The work done by the gas is about 30 L.atm

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

Ver imagen johanrusli
Lanuel

The work energy, w, gained or lost by the system when the gas expands is 30 Joules.

Given the following data:

  • Pressure = 1.5 atm
  • Initial volume = 15 liters
  • Final volume = 35 liters

To find the work energy, w, gained or lost by the system when the gas expands:

Mathematically, the work energy by a system is given by the formula:

[tex]Work = P \delta V[/tex]

Where:

  • P is the pressure.
  • V is the volume.

Substituting the given parameters into the formula, we have;

[tex]Work\;energy = 1.5(35-15)\\\\Work\;energy = 1.5(20)[/tex]

Work energy = 30 Joules.

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