Respuesta :
The work done by the gas is about 30 L.atm
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Further explanation
The Ideal Gas Law and Work formula that needs to be recalled is:
[tex]\boxed {PV = nRT}[/tex]
[tex]\boxed { W = P \Delta V }[/tex]
where:
W = Work ( J )
P = Pressure ( Pa )
V = Volume ( m³ )
n = number of moles ( moles )
R = Gas Constant ( 8.314 J/mol K )
T = Absolute Temperature ( K )
Let us now tackle the problem !
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Given:
initial volume = Vo = 15 L
final volume = V = 35 L
constant pressure = P = 1.5 atm
Asked:
word done by the gas = W = ?
Solution:
[tex]W = P \Delta V[/tex]
[tex]W = P \times ( V - Vo )[/tex]
[tex]W = 1.5 \times ( 35 - 15 )[/tex]
[tex]W = 1.5 \times 20[/tex]
[tex]W = 30 \texttt{ L.atm }[/tex]
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Conclusion:
The work done by the gas is about 30 L.atm
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
The work energy, w, gained or lost by the system when the gas expands is 30 Joules.
Given the following data:
- Pressure = 1.5 atm
- Initial volume = 15 liters
- Final volume = 35 liters
To find the work energy, w, gained or lost by the system when the gas expands:
Mathematically, the work energy by a system is given by the formula:
[tex]Work = P \delta V[/tex]
Where:
- P is the pressure.
- V is the volume.
Substituting the given parameters into the formula, we have;
[tex]Work\;energy = 1.5(35-15)\\\\Work\;energy = 1.5(20)[/tex]
Work energy = 30 Joules.
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