Answer with explanation:
Vertices of Rhombus, KM LN, are : K (w,0), M (w,v) , L (u,z) and N (?).
N (?)= (x,y)
Diagonals of Rhombus Bisect each other.Diagonal, KL and MN will Bisect each other.
Mid Point Formula of Line Joining , (m,n ) and (r,s) is :
[tex]=(\frac{m+r}{2},\frac{n+s}{2})[/tex]
Mid Point of KL is
[tex]=(\frac{w+u}{2},\frac{0+z}{2})[/tex]
Mid Point of MN is
[tex]=(\frac{w+x}{2},\frac{v+y}{2})[/tex]
So, Mid point of KL = Mid Point of MN
[tex](\frac{w+u}{2},\frac{0+z}{2})=(\frac{w+x}{2},\frac{v+y}{2})\\\\ \frac{w+u}{2}=\frac{w+x}{2}\\\\x=u\\\\\frac{0+z}{2}=\frac{v+y}{2}\\\\y=z-v[/tex]
So, coordinates of Point N,can be = (u, z-v).
None, of the Option,matches with the given option.
If you will Write the rhombus as,K L MN,then also you will not get answer which matches with the options.
