An equation in standard form for an ellipse with its center at the origin, a vertex at (13, 0), and a focus at (12, 0) is [tex]\bold{\frac{x^2}{169} +\frac{y^2}{25} =1}[/tex]
The correct answer is option (A)
What is equation of ellipse?
"The standard form of equation of ellipse with center (0, 0) is, [tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex]
What are vertices of the standard ellipse?
"The vertices of the standard ellipse [tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex] are [tex](\pm a,0)[/tex] "
What is focus of the standard ellipse?
"The foci of the standard ellipse [tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex] are [tex](\pm c,0)[/tex], where [tex]c^{2} =a^{2}- b^{2}[/tex] "
For given question,
The center of the ellipse is at the origin.
Using the standard form of equation of the ellipse,
[tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex]
A vertex at (13, 0)
⇒ (a, 0) = (13, 0)
⇒ a = 13
And a focus at (12, 0).
⇒ (c, 0) = (12, 0)
⇒ c = 12
We know, [tex]c^{2}= a^{2}- b^{2}[/tex]
Now, we find the value of b i.e., minor axis
[tex]\Rightarrow 12^{2} =13^{2}- b^{2}\\\\\Rightarrow b^2=169-144\\\\ \Rightarrow b^2=25\\\\\Rightarrow b=\pm 5[/tex]
Substituting these values in the standard form of equation of ellipse with center (0, 0),
[tex]\Rightarrow \frac{x^2}{a^2} +\frac{y^2}{b^2} =1\\\\\Rightarrow \bold{\frac{x^2}{169} +\frac{y^2}{25} =1}[/tex]
Therefore, an equation in standard form for an ellipse with its center at the origin, a vertex at (13, 0), and a focus at (12, 0) is [tex]\bold{\frac{x^2}{169} +\frac{y^2}{25} =1}[/tex]
The correct answer is option (A)
Learn more about ellipse here:
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