Answer:
The value of bc is 5.9 units.
Step-by-step explanation:
Given information: b is between a and c, ac=15.8 and ab=9.9.
We need to find the measure of bc.
Since b is between a and c, therefore the segment ac is the sum of two segments ab and bc.
[tex]ac=ab+bc[/tex]
Substitute ac=15.8 and ab=9.9 in the above equation.
[tex]15.8=9.9+bc[/tex]
Subtract 9.9 from both sides.
[tex]15.8-9.9=9.9+bc-9.9[/tex]
[tex]5.9=bc[/tex]
Therefore the value of bc is 5.9 units.
If assumption of Collinearity is not for granted, then the length of Segment BC is defined by [tex]BC = \sqrt{347.65 -312.84\cdot \cos \beta}[/tex], for [tex]\beta \in [0^{\circ}, 180^{\circ}][/tex].
Reminder - Given that statement seems to be incomplete, we assume that we are talking about Line Segments and that Segments AC and BC may be Collinear.
By Geometry and, being more specific, by definition of Triangles, if we assume that all segment are not necessarily Collinear, then a Triangle may exist and can be modelled by the Law of Cosine:
[tex]BC = \sqrt{AC^{2}+AB^{2}-2\cdot AC\cdot AB\cdot \cos \beta}[/tex] (2)
Where [tex]\beta[/tex] is the angle at point B, in sexagesimal degrees and is between 0° and 180°.
If we know that [tex]AC = 15.8[/tex] and [tex]AB = 9.9[/tex], then the expression for the length of BC is:
[tex]BC = \sqrt{347.65 -312.84\cdot \cos \beta}[/tex]
If assumption of Collinearity is not for granted, then the length of Segment BC is defined by [tex]BC = \sqrt{347.65 -312.84\cdot \cos \beta}[/tex], for [tex]\beta \in [0^{\circ}, 180^{\circ}][/tex].
Please see this question related to Triangles: https://brainly.com/question/24160832
