Answer:
There are [tex]9.27 \times 10^{23}[/tex] atoms of O in 42.2 grams of C₆H₁₂O₆
Explanation:
1. How many grams of O in 46.2 grams of [tex]C_6H_{12}O_6[/tex]. There are 96g in 180g (1 mol) of [tex]C_6H_{12}O_6[/tex]:
[tex]96g \rightarrow 180g\\xg \rightarrow 46.2g\\180x = 4435.2\\x = 24.64[/tex]
There are 24.64g of O in 42.2g of [tex]C_6H_{12}O_6[/tex]
2. How many moles of O are in 24.64g of O.
[tex]1 \text{ mol} \rightarrow 16g\\x \text{ mol} \rightarrow 24.64g\\16x = 24.64\\x = 1.54[/tex]
3. How many particles (atoms) of O are in 1.54 mol
[tex]1 \text{ mol} \rightarrow 6.02 \times 10^{23}\\1.54\text{ mol} \rightarrow x\\x = 9.27\times 10^{23}[/tex]