Respuesta :
In 11 sided Polygon no. of sides = 11
In general sum of interior angle of any polygon = [tex](n-2)*180[/tex]
Where n is no. of sides in polygon.
We can find value of each interior angle in any polygon as
[tex] \frac{(n-2)*180}{n} [/tex]
For polygon of 11 sides
Value of each interior angle is
[tex] \frac{(11-2)*180}{11} [/tex]
[tex] \frac{9*180}{11} = \frac{1620}{11} = 147.272727..... [/tex]
So value of each interior angle in 11 sided polygon is 147.272727..... which we can round it as 147.28 degree.
Value of exterior angle in polygon = 180 - interior angle
= 180 - 147.28 = 32.72 degree.
So the value of exterior angle in 11 sided polygon is = 32.72 degree.
In general sum of interior angle of any polygon = [tex](n-2)*180[/tex]
Where n is no. of sides in polygon.
We can find value of each interior angle in any polygon as
[tex] \frac{(n-2)*180}{n} [/tex]
For polygon of 11 sides
Value of each interior angle is
[tex] \frac{(11-2)*180}{11} [/tex]
[tex] \frac{9*180}{11} = \frac{1620}{11} = 147.272727..... [/tex]
So value of each interior angle in 11 sided polygon is 147.272727..... which we can round it as 147.28 degree.
Value of exterior angle in polygon = 180 - interior angle
= 180 - 147.28 = 32.72 degree.
So the value of exterior angle in 11 sided polygon is = 32.72 degree.
