Two rectangles are similar. One has a length of 12 cm and a width of 9 cm, and the other has a width of 8 cm. Find the length of the second rectangle. Round to the nearest tenth if necessary.

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The lengths of the sides of similar rectangles are proportional:
[tex]\frac{l_1}{w_1}=\frac{l_2}{w_2} \\ \\ \frac{12}{9}=\frac{x}{8} \\ \\ \frac{12}{9} \times 8 = x \\ \\ \frac{96}{9}= x \\ \\ x \approx 10.7[/tex]

The length of the second rectangle is approximately 10.7 cm.

Answer:

around 10.7 cm