Respuesta :
The four consecutive even integers are: x, x+2, x+4, and x+6.
x+x+2+x+4+x+6 = 244
4x+12 = 244
4x= 232, x = 58.
The four integers are: 58, 60, 62, and 64
x+x+2+x+4+x+6 = 244
4x+12 = 244
4x= 232, x = 58.
The four integers are: 58, 60, 62, and 64
Four consecutive even integers are 58, 60, 62, 64.
What are consecutive even integers?
Consecutive even integers are even integers that follow each other by a difference of 2. If x is an even integer, then x + 2, x + 4, x + 6 and x + 8 are consecutive even integers.
Four consecutive even integers:
To attempt to find four such integers, you could solve 244 = n +(n + 2) + (n + 4) + (n + 6) and find that the resulting n isn't an integer. So there are no such four consecutive even integers.
If there are four such integers then they are of the form n, n + 2, n + 4 and n + 6.
Then we have:
244 = n +(n + 2) + (n + 4) + (n + 6)
244 = 4n + 12
Subtract 12 from both sides to get:
244 - 12 = 4n + 12 - 12
232 = 4n
Divide both sides by 4 to get:
n = 58
n + 2 = 58 + 2 = 60
n + 4 = 58 + 4 = 62
n + 6 = 58 + 6 = 64
Four consecutive even integers are 58, 60, 62, 64.
Find out more information about consecutive even integers here
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