Given that Bill
is on the school archery team. the target has a center bull's-eye and
two rings around the bull's-eye.
Given the table below that gives the probabilities of outcomes.
[tex]\begin{tabular}
{|c|c|c|c|c|}
\bold{Outcome}&Bull's-eye&Inner ring&Outer ring&Miss\\
\bold{Probability}&0.036&0.297& 0.423&0.244
\end{tabular}[/tex]
The probability that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72
Therefore, the probability that Bill will get the next arrow in the inner or outer ring is 0.72
