Respuesta :
Answer : The concentration of the [tex]KOH[/tex] is, 0.115 M
Explanation :
Using dilution law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity of an acid = 1
[tex]n_2[/tex] = acidity of a base = 1
[tex]M_1[/tex] = concentration of [tex]HClO_4[/tex] = 0.125 M
[tex]M_2[/tex] = concentration of KOH = ?
[tex]V_1[/tex] = volume of [tex]HClO_4[/tex] = 25 ml
[tex]V_2[/tex] = volume of NaOH = 27.07 ml
Now put all the given values in the above law, we get the concentration of the [tex]KOH[/tex].
[tex]1\times 0.125M\times 25ml=1\times M_2\times 27.07ml[/tex]
[tex]M_2=0.115M[/tex]
Therefore, the concentration of the [tex]KOH[/tex] is, 0.115 M
The concentration of 27.07ml of KOH solution requires to titrate 25mL of 0.125 M HClO₄ is 0.115 M.
How do we calculate the concentration?
Concentration of any solution in the titration will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ is the molarity and volume of HClO₄ and M₂ & V₂ is the molarity and volume of KOH solution. Now putting values from the question on the above equation, we get
M₂ = (0.125)(25) / (27.07) = 0.115 M
Hence required concentration of KOH is 0.115M.
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