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coolstick
In the point (x, y), if x=0, then the point is on the y axis.
If y=0, the point is on the x axis
If both x and y are positive (greater than 0), the point is in quadrant 1
If x is negative (less than 0) and y is positive (greater than 0), the point is in quadrant 2
If both x and y are negative, the point is in quadrant 3
If x is positive and y is negative, the point is in quadrant 4

Taking (-3, 2), since 3 has a - sign before it (and nothing else), it is negative. Since the x value comes first, this means that x is negative. Since it simply states "2" for the y value, it is positive. As x is negative and y is positive, we know that the point is in quadrant 2.

I challenge you to do this on your own - good luck, and feel free to ask with further questions!
calculista

Answer:

Part 1) [tex](0,16)[/tex] is located on the Y-axis

Part 2) [tex](2,-12)[/tex] is located on the IV quadrant

Part 3) [tex](-1,2)[/tex] is located on the II quadrant

Part 4) [tex](3,0)[/tex] is located on the X-axis

Part 5) [tex](36.7,3.9)[/tex] is located on the I quadrant

Part 6) [tex](-\frac{5}{8}, -5\frac{1}{3})[/tex] is located on the III quadrant

Step-by-step explanation:

we know that

I Quadrant

The x-coordinate and the y-coordinate are both positive

II Quadrant

The x-coordinate is negative and the y-coordinate is positive

III Quadrant

The x-coordinate and the y-coordinate are both negative

IV Quadrant

The x-coordinate is positive and the y-coordinate is negative

X-axis

The y-coordinate is equal to zero

Y-axis

The x-coordinate is equal to zero

Part 1) point [tex](0,16)[/tex]

The point is located on the Y-axis

Part 2) point [tex](2,-12)[/tex]

The point is located on the IV quadrant

Part 3) point [tex](-1,2)[/tex]

The point is located on the II quadrant

Part 4) point [tex](3,0)[/tex]

The point is located on the X-axis

Part 5) point [tex](36.7,3.9)[/tex]

The point is located on the I quadrant

Part 6) point [tex](-\frac{5}{8}, -5\frac{1}{3})[/tex]

The point is located on the III quadrant

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