Respuesta :
F(friction) = u F(normal)
so, F(friction) = (.30)(60*9.81) = 177 N
F = ma
so, 177 = (60)a, a = 177/60 = 2.9m/s^2
v(final)^2 = v(initial)^2+2ax
so, 0 = 1.5^2 + 2(-2.9)x, x = 2.25/(2*-2.9) = -.38793 the negative indicates that the direction of accel is opposite of direction of speed.
-0.39 meters is the answer.
so, F(friction) = (.30)(60*9.81) = 177 N
F = ma
so, 177 = (60)a, a = 177/60 = 2.9m/s^2
v(final)^2 = v(initial)^2+2ax
so, 0 = 1.5^2 + 2(-2.9)x, x = 2.25/(2*-2.9) = -.38793 the negative indicates that the direction of accel is opposite of direction of speed.
-0.39 meters is the answer.
Answer:
S = 0.39 m
Explanation:
Solution is attached