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Look at points C and D on the graph: Coordinate grid shown from negative 6 to positive 6 in increments of 1 on both the axes. A line is drawn by connecting point C at negative 2, 0 and point D at 3, 5 What is the distance (in units) between points C and D? Round your answer to the nearest hundredth.
2.24
3.16
6.40
7.07

Respuesta :

tristanlongoria
Let's see...
[tex]d= \sqrt{(3-(-2))^{2} + (5-0)^2} \\ d=\sqrt{(5)^{2}+(5)^{2}} \\ d=\sqrt{25+25} \\ d=\sqrt{50} \\ d=7.071, or 7.07[/tex]
JeanaShupp

Answer: 7.07 units.

Step-by-step explanation:

The distance between any two point (a,b) and (c,d) on coordinate plane is given by :-

[tex]\text{Distance=}\sqrt{(d-b)^2+(c-a)^2}[/tex]

By considering the given information , we have

C= (-2,0) and  D = (3,5)

Then, the distance (in units) between points C and D will be :

[tex]CD=\sqrt{(5-0)^2+(3-(-2))^2}[/tex]

[tex]\Rightarrow\ CD=\sqrt{(5)^2+(3+2)^2}[/tex]

[tex]\Rightarrow\ CD=\sqrt{25+25}[/tex]

[tex]\Rightarrow\ CD=\sqrt{50}=7.07106781187\approx7.07[/tex]

[Rounded to the nearest hundredth]

Hence, the distance (in units) between points C and D = 7.07 units.

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