Respuesta :
Answer:
SS' = 2.5
Step-by-step explanation:
The distances on segment QS' are 2/1.2 = 5/3 times those of corresponding parts on segment QT'.
5/3 · 1.5 = 2.5
Answer: x = 2.5 units
Step-by-step explanation:
Given : Line segment ST is dilated to create line segment S'T' using the dilation rule[tex]D_{Q, 2.25}[/tex].
TQ = 1.2 units, TT'=1.5 ,SQ = 2 units, SS' = x units.
We know that , dilation creates similar figures.
If we consider the given situation, we get
⇒ ΔSTQ and ΔS'T'Q must be similar.
Corresponding sides of similar triangle must be proportional .
[tex]\Rightarrow\ \dfrac{TQ}{TT'}=\dfrac{SQ}{SS'}\\\\\Rightarrow\dfrac{1.2}{1.5}=\dfrac{2}{x}\\\\\Rightarrow\ x=\dfrac{2}{1.2}\times1.5\\\\\Rightarrow\ x=2.5[/tex]
Hence, the distance between points S and S = 2.5 units