Respuesta :

Mcawesom
31.
[tex]5 \sqrt{6} - 3 \sqrt{6} = 2 \sqrt{6} [/tex]
32.
[tex] \sqrt{2} ( \sqrt{8} + \sqrt{6} ) \\ \sqrt{16} + \sqrt{12} \\ 4 + 2 \sqrt{3} [/tex]
33.
[tex](3 \sqrt{2} - 2 \sqrt{5} )(4 \sqrt{2} + 2 \sqrt{5} ) \\ 12 \sqrt{4} + 6 \sqrt{10} - 8 \sqrt{10} - 4 \sqrt{25} \\ 24 - 2 \sqrt{10} - 20 \\ 4 - 2 \sqrt{10} [/tex]
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