The integers are [tex]\boxed{52}[/tex], [tex]\boxed{53}[/tex] and [tex]\boxed{54}[/tex].
Further explanation:
Given:
The sum of the first two is 51 more than the third.
Explanation:
Consider the first integers as [tex]x[/tex].
So the second integers is [tex]x+1.[/tex]
Therefore, the third integers is [tex]x+2.[/tex]
Given that the sum of first two numbers is 51 more than the third.
[tex]\begin{aligned}\left( x \right) + \left( {x + 1} \right) &= 51 + \left( {x + 2} \right)\\x + x + 1 &= 51 + x + 2\\2x + 1 &= 53 + x\\2x - x &= 53 - 1 \\x&= 52\\\end{aligned}[/tex]
The first integer is 52.
The second integer can be calculated as,
[tex]\begin{aligned}{\text{Second integer}} &= x + 1\\&= 52 + 1\\&= 53\\\end{aligned}[/tex]
The second integer can be calculated as,
[tex]\begin{aligned}{\text{Third integer}}&= x + 2\\&= 52 + 2\\&= 54\\\end{aligned}[/tex]
Hence, the integers are [tex]\boxed{52}, \boxed{53}[/tex] and [tex]\boxed{54}.[/tex]
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Answer details:
Grade: High school
Subject: Mathematics
Chapter: Linear equation
Keywords: Three consecutive, consecutive, sum, addition, integers, more, 51 more, consecutive integers, first two.
