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When 125 ml of 0.500 m agno3 is added to 100. ml of 0.300 m nh4cl, how many grams of agcl are formed? agno3(aq) + nh4cl(aq) → agcl(s) + nh4no3(aq)?

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Kalahira
Answer: 125 mL of 0.5M AgNO3 = 2 mol AgNO3 100mL of 0.3M NH4Cl = 3 mol NH4Cl AgNO3 + NH4Cl ⇒ AgCl + NH4NO3 mol AgCl = (1/1) 2 = 2 mol mol NH4Cl still remaining = 3 - 2 = 1 mol

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