Direct variation: y = kx
Inverse variation: y = k/x
y varies directly with x^2 ... : y = kx^2
... and inversely with z: y = kx^2/z
Now we use the given information to find k.
x = 2, z = 6, y = 2 6/11
y = kx^2/z
2 6/11 = k * (2^2)/6
28/11 = 4k/6
28/11 = 2k/3
k = 28/11 * 3/2
k = 84/22 = 42/11
Now we can use our value of k in the function.
y = kx^2/z
y = (42/11)(x^2/z)
Now we use our function to find y when x = 1 and z = 3.
y = (42/11)(x^2/z)
y = (42/11)(1^1/3)
y = 42/33
y = 14/11
y = 1 3/11