Respuesta :
triangle HVD is similar to triangle TVU. ratio of corresponding sides are equal
[tex] \frac{vd}{vu} = \frac{hd}{tu} [/tex]
Since D is the midpoint of VU, VD=40
[tex] \frac{40}{80} = \frac{80}{tu} [/tex]
40(TU)=80(80)
[tex]tu = \frac{80 \times 80}{40} \\ tu = 160[/tex]
[tex] \frac{vd}{vu} = \frac{hd}{tu} [/tex]
Since D is the midpoint of VU, VD=40
[tex] \frac{40}{80} = \frac{80}{tu} [/tex]
40(TU)=80(80)
[tex]tu = \frac{80 \times 80}{40} \\ tu = 160[/tex]
The required length of TU is 160.
Given that,
Points E, D, and H are the midpoints of triangle TUV.
UV = 80, TV = 100, and HD = 80.
We have to determine,
The length of TU.
According to the question,
Points E, D, and H are the midpoints of triangle TUV.
In the triangle, HVD is similar to triangle TVU. the ratio of corresponding sides is equal.
Then,
[tex]\dfrac{VD}{VU} = \dfrac{HD}{TU}[/tex]
Here, The length of VU = 80 and VD is half of VU = 40
Substitute the values in the equation,
[tex]\dfrac{40}{80} = \dfrac{80}{TU}\\\\TU = \dfrac{80 \times 80}{40}\\\\TU = 160[/tex]
Hence, The required length of TU is 160.
To know more about Triangles click the link given below.
https://brainly.com/question/1863222