check the picture below.
the triangle is an isosceles, meaning it has two twin sides, that make two twin angles, namely AB = BC, and the angles at A and C are twins as well.
now, the AD segment, is an angle bisector, meaning it cuts the angle at A in two equal halves, so if say the angles are x° each, then the bisectors cuts it in (x/2)°.
now, we know ∡ADB is 110°, therefore its supplementary angle, in green, is 70°.
recall that the sum of all interior angles in a triangle is 180°, thus
[tex]\bf 70~+~\cfrac{x}{2}+x=180\impliedby \textit{let's multiply both sides by the LCD 2}
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2\left( 70~+~\cfrac{x}{2}+x \right)=2(180)\implies 140+x+2x=360
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3x=220\implies x=\cfrac{220}{3}\implies x=73\frac{1}{3}\\\\
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\measuredangle B+x+x=180\implies \measuredangle B+\cfrac{220}{3}+\cfrac{220}{3}=180
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\measuredangle B=180-\cfrac{440}{3}
\implies
\measuredangle B=\cfrac{540-440}{3}\implies \measuredangle B=\cfrac{100}{3}
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\measuredangle B=33\frac{1}{3}[/tex]
