This is about mathematical reasoning.
A) When tables are apart; c = 6t
B) when tables are joined end to end; c = 4t + 2
- A) He can fit 6 chairs around a table.
Let's denote table with t and chair with c.
Thus;
When t = 1, c = 6.
They will be arranged in the form of 2 along each of the longer sides and 1 at each of the smaller sides.
- When 2 tables are placed end to end, we will have 2 smaller sides for chairs and 4 longer sides. This means the 4 longer sides will each take 2 chairs = 8 chairs while the 2 smaller sides will each take 1 chair which is 2 in total.
Thus; when tables are joined end to end and t = 2, c = 10
- Similarly, when 3 tables are placed end to end, we will have 2 smaller sides for chairs and 6 longer sides. This means the 6 longer sides will each take 2 chairs = 12 chairs while the 2 smaller sides will each take 1 chair which is 2 in total.
Thus; when 3 tables are joined end to end; t = 3, c = 14
We can see that;
t = 1, c = 6
t = 2, c = 10
t = 3, c = 14
We can deduce a formula from this trend when tables are joined end to end as;
c = 4t + 2
- B) since t = tables and c = chairs. If the tables are separated, it means if one table can take 6 chairs, then 2 tables can take 6 × 2 = 12 chairs.
Thus, we can say the formula is c = 6t.
Read more at; brainly.in/question/12963987
