Respuesta :
1 Method is to solve for y so the inequality will resemble slope - intercept form: y = mx + b
[tex]2x- \frac{1}{4} y\ \textless \ 1[/tex]
(1) Get rid of the fraction by multiplying the entire inequality by 4 (LCD)
Result: 8x - y < 1
(2) Use the opposite of 8x to move that term to the other side
Result: - y < - 8x + 1
(3) Divide each term by -1 (coefficient of y) *Remember to reverse inequality sign
Result: y > 8x - 1
(4) y-int (b = -1) plot this on the y-axis
(5) slope 8 or [tex] \frac{8}{1} [/tex] means from the y-int value move up 8 then to the right 1 and put a 2nd point
(6) Now it's time to draw a line thru the two points and if the inequality sign < or > you make a dashed (broken) line thru the points
(7) Now where to shade.... look at (3) y > so shade above the line
[tex]2x- \frac{1}{4} y\ \textless \ 1[/tex]
(1) Get rid of the fraction by multiplying the entire inequality by 4 (LCD)
Result: 8x - y < 1
(2) Use the opposite of 8x to move that term to the other side
Result: - y < - 8x + 1
(3) Divide each term by -1 (coefficient of y) *Remember to reverse inequality sign
Result: y > 8x - 1
(4) y-int (b = -1) plot this on the y-axis
(5) slope 8 or [tex] \frac{8}{1} [/tex] means from the y-int value move up 8 then to the right 1 and put a 2nd point
(6) Now it's time to draw a line thru the two points and if the inequality sign < or > you make a dashed (broken) line thru the points
(7) Now where to shade.... look at (3) y > so shade above the line
