Respuesta :

Noah11012
Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) [tex] \leq [/tex] -2x + 6
4x - 24 [tex] \leq [/tex]  -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24  [tex] \leq [/tex] -2x + 6
6x - 24  [tex] \leq [/tex]  6    <-- Add 2x to both sides
6x         [tex] \leq [/tex]  30  <-- Add 24 to both sides 
x           [tex] \leq [/tex] 5    <-- Divide both sides by 6

In order to be in the solution set, x has to be less than or equal to 5.

In interval notation: [5, -∞)

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