To be on the unit circle, the value of x must be 1/2 or -1/2.
How to find the value of x?
If the point (x, √(3)/2) is on the unit circle, then its magnitude must be equal to 1.
The magnitude of a point (x, y) is:
[tex]M = \sqrt{x^2 + y^2}[/tex]
Then we must have:
[tex]1 = \sqrt{x^2 + (\sqrt{3} /2})^2) \\ \\1 = x^2 + 3/4\\\\1 - 3/4 = x^2 = 1/4\\\\x = \pm 1/2[/tex]
Then x can be 1/2 or -1/2.
If you want to learn more about circles:
https://brainly.com/question/1559324
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