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What are the missing reasons in the proof. Given parallelogram ABCD with diagonal BD and prove triangle ABD is congruent with triangle CDB

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Answer:

By SSS congruency rule ΔABD ≅ ΔCBD

Step-by-step explanation:

Given parallelogram ABCD with diagonal BD. we have to prove that ABD is congruent with triangle CDB.

In ΔABD and ΔCBD

AD=BC       (Opposite sides of parallelogram)

AB=DC        (Opposite sides of parallelogram)

DB=DB        (common)

All three sides are equal.

Hence, By SSS congruency rule ΔABD ≅ ΔCBD


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