Answer:
Amaro has the most number of cards with him.
Step-by-step explanation:
Let Amaro has x cards
[tex]\text{Now, Mateo has }\frac{1}{2}\text{ as many cards as Amaro}\\\\\implies \text{Mateo has }\frac{1}{2}\times x = \frac{x}{2} \text{ cards}\\\\\text{Also, Augustin has }\frac{1}{4}\text{ as many cards as Mateo}\\\\\implies \text{Augustin has }\frac{1}{4}\times \frac{x}{2}=\frac{x}{8}\text{ cards}\\\\\text{Therefore, Amaro has x cards, Mateo has }\frac{x}{2}\text{ cards and Augustin has }\frac{x}{8}\text{ cards}[/tex]
Since, x is the number of cards so cannot be negative quantity.
[tex]\implies x >\frac{x}{2}>\frac{x}{8}[/tex]
Hence, Amaro has the most number of cards with him.
