Find perimeter of the rectangle PQRS formed by points of intersection of parabolas y=2x^2−12 and y=−3x^2+8 and their projections on the x-axis.

Respuesta :

using a graphical tool------ >see attached drawing

points of intersection of parabolas are--------->point P and point Q
point P(-2,-4)     point Q(2,-4)

their projections on the x-axis. are---- > point R and point S
point R(-2,0)      point S(2,0)

the sides length of of the rectangle are
PQ=RS= 4
PR=QS=4
Perimeter=PQ+RS+PR+QS=16

the answer is 16




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