Let, the amount of money Schyler has be $x.
Given, Truth has $3 more than twice as much money as Schyler.
So Truth has the amount of money = $[tex] (2x+3) [/tex]
Given Truth has $10 amount of money.
We can write it as an equation. The equation will be,
[tex] 2x+3 = 10 [/tex]
To find x, first we have to move 3 to the right side. 3 is added there. To move it we will use reverse operation of addition. Reverse operation of addition is subtraction. So we will subtract 3 from both sides first.
[tex] 2x+3-3 = 10-3 [/tex]
[tex] 2x = 10-3 [/tex]
[tex] 2x = 7 [/tex]
Now to find x , we will move 2 to the other side by using division. We will get,
[tex] \frac{2x}{2} = \frac{7}{2} [/tex]
[tex] x = \frac{7}{2} [/tex]
[tex] x = 3.5 [/tex]
We have got the required answer.
The amount of money Schyler has $3.5.
