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How much work is done by the force lifting a
0.1-kilogram hamburger vertically upward at
constant velocity 0.3 meter from a table?
(1) 0.03 J (3) 0.3 J
(2) 0.1 J (4) 0.4 J

Respuesta :

skyluke89

The work done in lifting the hamburger is equal to the increase in gravitational potential energy of the hamburger, given by

[tex] W=\Delta U=mg \Delta h [/tex]

where

m=0.1 kg is the mass of the hamburger

[tex] g=9.81 m/s^2 [/tex] is the gravitational acceleration

[tex] \Delta h=0.3 m [/tex] is the increase in height of the hamburger


Substituting numbers into the equation, we find

[tex] W=(0.1 kg)(9.81 m/s^2)(0.3 m)=0.3 J [/tex]


So, the correct answer is

(3) 0.3 J

asuwafohjames

The workdone by the force is 0.3 J and the right option is (3) 0.3 J.

To calculate the workdone by the force, we use the formula below.

Formula:

  • W = mgh................. Equation 1

Where:

  • W = workdone by the force
  • m = mass of the hamburger
  • h = vertical height
  • g = acceleration due to gravity

From the question,

Given:

  • m = 0.1 kg
  • h = 0.3 meter
  • g = 10 m/s².

Substitute these values into equation 1

  • W = (0.1)(0.3)(10)
  • W = 0.3 J.

Hence, The workdone by the force is 0.3 J and the right option is (3) 0.3 J.  

Learn more about workdone here: https://brainly.com/question/18762601

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