Answer:
Option 4
Step-by-step explanation:
Given : d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.
To find : The correct simplification
Solution :
d to the 7th power = [tex]d^7[/tex]
g to the 13th power = [tex]g^{13}[/tex]
d to the 7th power times g to the 13th power = [tex]d^7\times g^{13}[/tex]
d to the 2nd power = [tex]d^2[/tex]
g to the 7th power = [tex]g^7[/tex]
d to the 2nd power times g to the 7th power = [tex]d^2\times g^{7}[/tex]
According to question,
d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.
[tex]=\frac{d^7\times g^{13}}{d^2\times g^7}[/tex]
[tex]=d^{7-2}\times g^{13-7}[/tex]
[tex]=d^{5}\times g^{6}[/tex]
Therefore, Option 4 is correct.
