Given
data set for Drew : [90,81,86,79,97,84,92], sorted : [79,81,84,86,90,92,97]
mean, μ 1 =(79+81+84+86+90+92+97)/7=87
Interquartile range, IQR 1 = (92-81)=11
data set for Nancy: [96,68,91,94,69,99,92], sorted : [68,69,91,92,94,96,99]
mean, μ 2 = (68+69+91+92+94+96+99)/7=87 Therefore the means are the same
Interquartile range, IQR 2 = 96-69 = 27 Therefore Nancy has a higher IQR
Note: There are different ways to calculate quartiles. Above method excludes median, which is how it is taught in many schools.