Respuesta :
The power (P) is defined as the work done by the engine per unit of time:
[tex]P= \frac{W}{t} [/tex]
Where W is the work and t the time. If the efficiency of the engine is 100% (like in this case), all the work done is converted into useful power, so we can use the previous equation. By rearranging it and by plugging in the numbers (P=23000 W and t=35 s), we can find the work done by the car engine:
[tex]W=Pt=(23000 W)(35 s)=8.05 \cdot 10^5 J[/tex]
[tex]P= \frac{W}{t} [/tex]
Where W is the work and t the time. If the efficiency of the engine is 100% (like in this case), all the work done is converted into useful power, so we can use the previous equation. By rearranging it and by plugging in the numbers (P=23000 W and t=35 s), we can find the work done by the car engine:
[tex]W=Pt=(23000 W)(35 s)=8.05 \cdot 10^5 J[/tex]
Answer:
Work done, W = 8,05,000 J
Explanation:
It is given that,
Power of car engine, P = 23,000 watt
Time taken, t = 35 s
The work done per unit time is called the power of the car engine.
[tex]P=\dfrac{W}{t}[/tex]
[tex]W=P.t[/tex]
[tex]W=23000\times 35[/tex]
W = 8,05,000 J
Hence, this is the required solution