f(x)=2+1.5^x
g(x) is a str. line joining (1,7) and (1,-1) (you MUST use those parentheses)
p(x) = is a str. line joining the points (2,0) and (4,2) (use those parentheses!)
Looking at g(x), we see that x does not change, but that y changes. Thus, this is the straight vertical line whose x-coordinate is x=1.
Looking at p(x), we see that the slope, m, is (2/2), or 1, and that the equation is thus y - 0 = 1(x-2), or y=x-2.
Determine where the lines representing p(x) and g(x) intersect: Since g(x) is a vertical line with x=2, we set x=2 in y=x-2, obtaining y=0.
So the graphs of p(x) and g(x) intersect at (1,0).
There is no solution to p(x). That's not an equation. But if you set p(x)=0, you can solve for x: 0=x-2, or x=2.
Part C: What is the solution to g(x)=f(x)? In other words, where does f(x)=2+1.5^x intersect the vertical line x=1? Set x=1 in f(x), obtaining f(x)=2+1.5^1, or f(x) = 2 + 1.5 = 3.5 (answer to C).
