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roots of 16x^2+7x+4=0 are alpha^2 & beta ^2 find the quadratic eqn whose roots are 1/alpha^2 and beta^2

Respuesta :

popalabdulqayou
x=1/a^2 and 1/b^2
so the equations are 16(1/a^2)^2+7(1/a)^2+4=0 and 16(1/b^2)^2+7(1/b^2)+4=0
then 16/a^4+7/a^2+4=0 and 16/b^4+7/b^2+4=0
Hope this loves.

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