Respuesta :
5x ^ 2 - 8x + 5 = 0
For this case, the first thing we must do is apply the resolver.
We have then:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
substituting we have:
x = (- (- 8) +/- root ((- 8) ^ 2 - 4 * (5) * (5))) / (2 * (5))
Rewriting:
x = (8 +/- root (64 - 100)) / (10)
x = (8 +/- root (-36)) / (10)
x = (8 +/- 6raiz (-1)) / (10)
x = (4 +/- 3 * i) / (5)
Answer:
The solutions are:
x1 = (4 + 3 * i) / (5)
x2 = (4 - 3 * i) / (5)
For this case, the first thing we must do is apply the resolver.
We have then:
x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
substituting we have:
x = (- (- 8) +/- root ((- 8) ^ 2 - 4 * (5) * (5))) / (2 * (5))
Rewriting:
x = (8 +/- root (64 - 100)) / (10)
x = (8 +/- root (-36)) / (10)
x = (8 +/- 6raiz (-1)) / (10)
x = (4 +/- 3 * i) / (5)
Answer:
The solutions are:
x1 = (4 + 3 * i) / (5)
x2 = (4 - 3 * i) / (5)
Answer: they are right...
Step-by-step explanation: I just took the test...