Respuesta :

Question 5:

[tex]\text {Surface Area = } 2( \frac{1}{2} \times 4 \times 4) + (4 + 4 + \sqrt{4^2 +4^2}) \times 8 = 125.6 \text{ yd}^2[/tex]

[tex]\text{Volume = } \frac{1}{2} \times 4 \times 4 \times 8 = 64 \text { yd}^3 [/tex]

Question 9:

[tex]\text {Surface Area = } 2( \frac{1}{2} \times 3 \times 7) + (3 + 7 + \sqrt{3^2 +7^2}) \times 6 = 126.6 \text{ mm}^2 [/tex]

[tex]\text{Volume = } \frac{1}{2} \times 3 \times 7 \times 6 = 63 \text { mm}^3 [/tex]
mendietajose513
Since the surface area takes places as a right triangle it would mean that it's half of a square so we know we should divide by 2 as the last step to finding the surface area. I take the length and the width and multiply them together. 3 times 7 equals 21 mm squared. 21 mm squared is the value and like I said. Your final step is to divide so I divide 21mm by 2 and I get 10. 5mm squared as my surface area. To get the height I simply multiply the length times the width times the height and divide by 2 since it's half of the area of a rectangle. 3 times 7 makes 21 and you multiply it again but this time with the height which is 6mm. 126 is the value we got. Our final step is to divide by 2 and we get the answer as 63 mm cubed.

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