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Question 4 the compound sodium sulfate is soluble in water. when this compound dissolves in water, which ion listed below would be present in solution? s2- na22+ o2- so42- none of the above

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Dejanras
Answer is: SO₄²⁻ would be present in solution.
Balanced chemical reaction (dissociation):
Na₂SO₄(aq) → 2Na⁺(aq) + SO₄²⁻(aq).
The compound sodium sulfate dissociates in water on sodium cations (there are two sodium atoms in one molecule of sodium sulfate), charge charge of +1 and sulfate ion, charge -2.

Answer:

[tex]SO_4^-[/tex]

Explanation:

The sodium sulfate compound corresponds to a water soluble salt.

When a salt dissolves it will dissociate into the ions that compose it.

It dissociates into Cations (positively charged ions) and anions (negatively charged ions)

Sodium sulfate formula

[tex]Na_2SO_4[/tex]

Sodium sulfate when dissolved in water

[tex]Na_2SO_4\stackrel{H_2O}{\longrightarrow} 2Na^+SO_4^-[/tex]

Ions present in the solution:

[tex]Na^+[/tex] Cation

[tex]SO_4^-[/tex] Anion

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