Respuesta :
False !
If [tex]x=4:[/tex]
[tex] \sqrt{2(4)+1+3}= \sqrt{12}\\\\\sqrt{12}\neq0[/tex]
In fact, the true answer is [tex]x=-2[/tex]
[tex]\sqrt{2x+1+3}=0\\\\\sqrt{2x+4}=0\\\\2x+4=0\\2x=-4\\x=-2[/tex]
If [tex]x=4:[/tex]
[tex] \sqrt{2(4)+1+3}= \sqrt{12}\\\\\sqrt{12}\neq0[/tex]
In fact, the true answer is [tex]x=-2[/tex]
[tex]\sqrt{2x+1+3}=0\\\\\sqrt{2x+4}=0\\\\2x+4=0\\2x=-4\\x=-2[/tex]
X is not 4
The correct answer would be x=-2
2x+1+3=0
2x+4=0
-4 -4
2x= -4
2 2
X=-2
Hope this helps!
The correct answer would be x=-2
2x+1+3=0
2x+4=0
-4 -4
2x= -4
2 2
X=-2
Hope this helps!