Answer:
[tex]5.65\times 10^{26} kg[/tex]
Explanation:
From Kepler's third law: Mass of the planet is given by:
[tex] M = \frac{4\pi ^2d^3}{GT^2}[/tex]
where, T is the time period of satellite revolving about the planet at a distance d. G is the gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²
Given, d = 1.87 × 10⁸ m
T = 82800 s
⇒[tex] M = \frac{4\pi ^2 (1.87\times 10^8)^3}{(6.67\times 10^{-11})(82800)^2}=5.65\times 10^{26} kg[/tex]
