Respuesta :

AlexTrusk

Answer:

-11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1

(would really, reallly appreciate the brainliest)

Step-by-step explanation:

2x+9 < 9

can be rewritten as

2x < 0

and therefore

x < 0

the other inequality states that x hat to be bigger then -12

so all integers that satisfy -12 < x < 0 are in the set we search, but be aware that -12 and 0 don't fall into this set, bc -12 for example isn't bigger than -12

CHERLYNnotCHERRY

Answer:

The integers that satisfy both inequalities are -5, -6, -7, -8, -9, -10 and -11.

Step-by-step explanation:

Firstly, you have to solve the inequality :

[tex]2x + 9 < 0 [/tex]

[tex]2x < - 9[/tex]

[tex]x < - \frac{9}{2} [/tex]

[tex]x < - 4.5[/tex]

Next, given that x is greater than -12 but smaller than -4.5 so the inequality for x is :

[tex] - 12 < x < - 4.5[/tex]

Integer is a positive or a negative number but 'cannot be written in the form of decimal'. So the integers that satisfy both inequalities are :

[tex] - 12 < x < - 4.5[/tex]

[tex]x = - 11, - 10, - 9, - 8, - 7, - 6, - 5[/tex]

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