Given :
Actual mass , [tex]m_e=436.8\ g[/tex] .
Three observations 460.9 g, 461.4 g, 459.0 g .
To Find :
The percent error of the student.
Solution :
Percent error is given by :
[tex]\%error=\sum \dfrac{|approx\ value -actual\ value |}{exact\ value}\times 100\\\\\%error=\dfrac{|460.9-436.8|+|461.4-436.8|+|459-436.8|}{436.8}\times 100\\\\\%error=\dfrac{70.9}{436.8}\times 100\\\\\%error=16.23\%[/tex]
Therefore , the percent error of the student is 16.23 % .
Hence , this is the required solution .
