contestada

A train travels with a constant speed of 35.0m/s for 5.00s. What is the magnitude of the train's acceleration? How far did the train travel during this time?

Respuesta :

Answer:

dada given

speed is 35m/s

time is 5s

acceleration =?

from a=∆v/t

a= 35m/s÷5s

a=7m/s^2

how far

from

velocity = displacement/time

35m/s=d/5s

distance is 175m